Homework Help ASAP
Submitted by Anonymous on 22 April 2005 - 12:58am.
Ok- these are mostly math problems. But I am really horrible at math, so any help would be appreciated.
1. The heat combustion of ethanol is 30 kilojoules per gram. Convert this value to kilocalories per mole. Show calculations.
2. The heat combustion of a sample of automotive gasoline is 46KJ/g. How many grams of this gasoline would have to be burned in order to generate enough heat to raise the temperature of 1079 grams of water from 10 degrees Celcius to 61 degrees Celcius? Show Calculations.
3. how would you prepare exactly 150ml of a 1.5 M NaCl solution from a 150ml aliquot of a 15% (W/V) NaCl solution? Show Calculations
Like I said any help would be greatly appreciated. ( (

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1. The heat combustion of ethanol is 30 kilojoules per gram. Convert this value to kilocalories per mole. Show calculations.
Easy one, here. First, find moles of ethanol. Ethanol, if I'm not mistaken is CH3CH2OH. The molecular weight of that is 66 g/mole. Take the 30g/66g/mole= ??? That would be your answer in kj/mole. (Note: not sure about the ethanol formula, a bit rusty on the organic stuff.)
2. The heat combustion of a sample of automotive gasoline is 46KJ/g. How many grams of this gasoline would have to be burned in order to generate enough heat to raise the temperature of 1079 grams of water from 10 degrees Celcius to 61 degrees Celcius? Show Calculations.
This is a bit tougher, but still easy. We're going to whip out good ol' q=mc(delta)t. We're looking for q. M= 1079, c=1, t=(61-10=51). Plug them in and get q. Take q, then I'd set up a proportion. q is in KJ. So ---> 46KJ/1g = ??KJ/??g (you will know the second KJ, so there's only one variable, the number of grams.) That will be your answer.
3. how would you prepare exactly 150ml of a 1.5 M NaCl solution from a 150ml aliquot of a 15% (W/V) NaCl solution? Show Calculations
This is a bit ugly, and a situation I'm not very familiar with. I don't want to steer you the wrong way. =(
Like I said any help would be greatly appreciated.
Thanks that did help out!! lol