## Counting Atoms and Balancing the problem

I need help with my homework! I need help answering this problem!

NaOH + H2CO => Na2CO3 + H2O
Na= 1 Na= 2
O= 1+1 O= 3+1
H= 1+2 H= 2
C= 1 C= 1

Please help me! I have to have the same amount of atoms on both sides of the problem!

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### Re: Counting Atoms and Balancing the problem

[quote="bandit800"]I need help with my homework! I need help answering this problem!

NaOH + H2CO => Na2CO3 + H2O
Na= 1[color=white]+SPACER++[/color] Na= 2
O= 1+1[color=white]SPACER++[/color] O= 3+1
H= 1+2[color=white]SPACER++[/color] H= 2
C= 1[color=white]+2SPACER++[/color] C= 1

Please help me! I have to have the same amount of atoms on both sides of the problem![/quote]
Either I'm being thick, or that reaction isn't possible.
Some sort of oxidising agent is required to remove those Hydrogens from the carbonyl (H[size=8]2[/size]CO)

So I would have to put:

2NaOH + H[size=8]2[/size]CO

Remember that both sides are always equal...

Think about it and treat it as a game.

Well it's not that fun!...

:wink:

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