## Chemistry Homework

**Anonymous**

How do I find the mass of AlCl3 that is produced when 510 grams of Al2O3 react with HCl according to the following equation:

Al2O3+6HCl -> 2AlCl3+3H2O

Thanks for any help that you can give.

How do I find the mass of AlCl3 that is produced when 510 grams of Al2O3 react with HCl according to the following equation:

Al2O3+6HCl -> 2AlCl3+3H2O

Thanks for any help that you can give.

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Martin17 (not verified)| 18 February 2008 - 7:30am## On one side of the equation

On one side of the equation Al

_{2}O_{3}+ 6HCl -> 2AlCl_{3}+ 3H_{2}O we have the molecular formula for Al_{2}O_{3}and on the other side we have the molecular formula for 2AlCl_{3}. Lets call these molecular weights P and Q. That means that we have a proportion 510/P= X/Q; therefore, 510 x Q = P x X. To solve for X we have (510 x Q)/P. You can find P by adding up twice the atomic weight of Al and adding 3 times the atomic weight of oxygen. Q will be twice the sum of the atomic weight of Al and 3 times the atomic weight of Cl.